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Exploring Algorithmic Solutions for the Independent Roman Domination Problem in Graphs

Published 4 Jul 2024 in math.CO and cs.DM | (2407.03831v2)

Abstract: Given a graph G=(V,E)G=(V,E), a function f:V→0,1,2f:V\to {0,1,2} is said to be a \emph{Roman Dominating function} if for every v∈Vv\in V with f(v)=0f(v)=0, there exists a vertex u∈N(v)u\in N(v) such that f(u)=2f(u)=2. A Roman Dominating function ff is said to be an \emph{Independent Roman Dominating function} (or IRDF), if V1∪V2V_1\cup V_2 forms an independent set, where Vi=v∈V ∣ f(v)=iV_i={v\in V~\vert~f(v)=i}, for i∈0,1,2i\in {0,1,2}. The total weight of ff is equal to ∑v∈Vf(v)\sum_{v\in V} f(v), and is denoted as w(f)w(f). The \emph{Independent Roman Domination Number} of GG, denoted by iR(G)i_R(G), is defined as min${w(f)~\vert~f$ is an IRDF of $G}$. For a given graph GG, the problem of computing iR(G)i_R(G) is defined as the \emph{Minimum Independent Roman Domination problem}. The problem is already known to be NP-hard for bipartite graphs. In this paper, we further study the algorithmic complexity of the problem. In this paper, we propose a polynomial-time algorithm to solve the Minimum Independent Roman Domination problem for distance-hereditary graphs, split graphs, and P4P_4-sparse graphs.

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