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Close relatives (of Feedback Vertex Set), revisited

Published 30 Jun 2021 in cs.DM, cs.CC, cs.DS, and math.CO | (2106.16015v1)

Abstract: At IPEC 2020, Bergougnoux, Bonnet, Brettell, and Kwon showed that a number of problems related to the classic Feedback Vertex Set (FVS) problem do not admit a 2o(klog⁡k)⋅nO(1)2^{o(k \log k)} \cdot n^{\mathcal{O}(1)}-time algorithm on graphs of treewidth at most kk, assuming the Exponential Time Hypothesis. This contrasts with the 3k⋅kO(1)⋅n3^{k} \cdot k^{\mathcal{O}(1)} \cdot n-time algorithm for FVS using the Cut&Count technique. During their live talk at IPEC 2020, Bergougnoux et al.~posed a number of open questions, which we answer in this work. - Subset Even Cycle Transversal, Subset Odd Cycle Transversal, Subset Feedback Vertex Set can be solved in time 2O(klog⁡k)⋅n2^{\mathcal{O}(k \log k)} \cdot n in graphs of treewidth at most kk. This matches a lower bound for Even Cycle Transversal of Bergougnoux et al.~and improves the polynomial factor in some of their upper bounds. - Subset Feedback Vertex Set and Node Multiway Cut can be solved in time 2O(klog⁡k)⋅n2^{\mathcal{O}(k \log k)} \cdot n, if the input graph is given as a clique-width expression of size nn and width kk. - Odd Cycle Transversal can be solved in time 4k⋅kO(1)⋅n4^k \cdot k^{\mathcal{O}(1)} \cdot n if the input graph is given as a clique-width expression of size nn and width kk. Furthermore, the existence of a constant ε>0\varepsilon > 0 and an algorithm performing this task in time (4−ε)k⋅nO(1)(4-\varepsilon)^k \cdot n^{\mathcal{O}(1)} would contradict the Strong Exponential Time Hypothesis.

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