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A Composition Theorem via Conflict Complexity

Published 10 Jan 2018 in cs.CC | (1801.03285v1)

Abstract: Let R(⋅)\R(\cdot) stand for the bounded-error randomized query complexity. We show that for any relation f⊆0,1<sup>n</sup>×Sf \subseteq {0,1}<sup>n</sup> \times \mathcal{S} and partial Boolean function g⊆0,1<sup>n</sup>×0,1g \subseteq {0,1}<sup>n</sup> \times {0,1}, R1/3(f∘g<sup>n)</sup>=Ω(R4/9(f)⋅R1/3(g))\R_{1/3}(f \circ g<sup>n)</sup> = \Omega(\R_{4/9}(f) \cdot \sqrt{\R_{1/3}(g)}). Independently of us, Gavinsky, Lee and Santha \cite{newcomp} proved this result. By an example demonstrated in their work, this bound is optimal. We prove our result by introducing a novel complexity measure called the \emph{conflict complexity} of a partial Boolean function gg, denoted by χ(g)\chi(g), which may be of independent interest. We show that χ(g)=Ω(R(g))\chi(g) = \Omega(\sqrt{\R(g)}) and R(f∘g<sup>n)</sup>=Ω(R(f)⋅χ(g))\R(f \circ g<sup>n)</sup> = \Omega(\R(f) \cdot \chi(g)).

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