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An O(n2log⁡(n)){\cal O}(n^2 \log(n)) algorithm for the weighted stable set problem in claw-free graphs

Published 23 Jan 2015 in cs.DM | (1501.05775v7)

Abstract: A graph G(V,E)G(V, E) is \emph{claw-free} if no vertex has three pairwise non-adjacent neighbours. The Maximum Weight Stable Set (MWSS) Problem in a claw-free graph is a natural generalization of the Matching Problem and has been shown to be polynomially solvable by Minty and Sbihi in 1980. In a remarkable paper, Faenza, Oriolo and Stauffer have shown that, in a two-step procedure, a claw-free graph can be first turned into a quasi-line graph by removing strips containing all the irregular nodes and then decomposed into \emph{{claw, net}-free} strips and strips with stability number at most three. Through this decomposition, the MWSS Problem can be solved in O(∣V∣(∣V∣log⁡∣V∣+∣E∣)){\cal O}(|V|(|V| \log |V| + |E|)) time. In this paper, we describe a direct decomposition of a claw-free graph into \emph{{claw, net}-free} strips and strips with stability number at most three which can be performed in O(∣V∣<sup>2){\cal O}(|V|<sup>2) time. In two companion papers we showed that the MWSS Problem can be solved in O(∣E∣log⁡∣V∣){\cal O}(|E| \log |V|) time in claw-free graphs with α(G)≤3\alpha(G) \le 3 and in O(∣V∣∣E∣){\cal O}(|V| \sqrt{|E|}) time in {claw, net}-free graphs with α(G)≥4\alpha(G) \ge 4. These results prove that the MWSS Problem in a claw-free graph can be solved in O(∣V∣<sup>2</sup>log⁡∣V∣){\cal O}(|V|<sup>2</sup> \log |V|) time, the same complexity of the best and long standing algorithm for the MWSS Problem in \emph{line graphs}.

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