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New upper bound on block sensitivity and certificate complexity in terms of sensitivity

Published 19 Jun 2013 in cs.CC | (1306.4466v2)

Abstract: Sensitivity \cite{CD82,CDR86} and block sensitivity \cite{Nisan91} are two important complexity measures of Boolean functions. A longstanding open problem in decision tree complexity, the "Sensitivity versus Block Sensitivity" question, proposed by Nisan and Szegedy \cite{Nisan94} in 1992, is whether these two complexity measures are polynomially related, i.e., whether bs(f)=O(s(f)<sup>O(1))bs(f)=O(s(f)<sup>{O(1)}). We prove an new upper bound on block sensitivity in terms of sensitivity: bs(f)2<sup>s(f)1</sup>s(f)bs(f) \leq 2<sup>{s(f)-1}</sup> s(f). Previously, the best upper bound on block sensitivity was bs(f)(e2π)e<sup>s(f)</sup>s(f)bs(f) \leq (\frac{e}{\sqrt{2\pi}}) e<sup>{s(f)}</sup> \sqrt{s(f)} by Kenyon and Kutin \cite{KK}. We also prove that if mins0(f),s1(f)\min{s_0(f),s_1(f)} is a constant, then sensitivity and block sensitivity are linearly related, i.e. bs(f)=O(s(f))bs(f)=O(s(f)).

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